下面程序的输出为（ ）。
#include <iostream>#define N 10using namespace std;int path[N][N];int main() { for (int i = 1; i < N; i++) path[i][0] = i; for (int j = 1; j < N; j++) path[0][j] = j; for (int i = 1; i < N; i++) for (int j = 1; j < N; j++) path[i][j] = path[i - 1][j] + path[i][j - 1]; cout << path[8][4] << endl; return 0;}