执行如下 C++ 代码，将从小到大依次输出 abs(N) 个整数，并在最后输出 1。
int N;cin >> N;int start_num = 1, end_num = N + 1, i; if (N < 0) start_num = N, end_num = 0; for (i = start_num; i < end_num; i++) cout << i << " "; cout << endl << ((i - 1) == abs(N)) << endl;执行如下 C++ 代码，将从小到大依次输出 abs(N) 个整数，并在最后输出 1。
int N;cin >> N;int start_num = 1, end_num = N + 1, i; if (N < 0) start_num = N, end_num = 0; for (i = start_num; i < end_num; i++) cout << i << " "; cout << endl << ((i - 1) == abs(N)) << endl;