求解鸡兔同笼。在如下 C++ 代码中，tou 代表鸡和兔的头总数，jiao 代表鸡和兔的脚总数。先后两个输
入均为正整数。该程序能求解鸡兔同笼。
int tou, jiao, tu_tou, ji_tou; cout << "请输入鸡和兔的头总数：";cin >> tou;cout << "请输入鸡和兔的脚总数：";cin >> jiao; for (tu_tou = 0; tu_tou < tou + 1; tu_tou++) { ji_tou = tou - tu_tou; if (tu_tou * 4 + ji_tou * 2 == jiao) printf("兔的数量=%d,鸡的数量=%d\n", tu_tou, ji_tou);}if (tu_tou == tou) printf("无解\n");