← 查看本卷题目
组合题6 个小题
已作答 0 / 6
#include <algorithm>#include <iostream>using namespace std; int n, a[1005]; struct Node{    int h, j, m, w;     Node(const int _h, const int _j, const int _m, const int _w):        h(_h), j(_j), m(_m), w(_w)    { }     Node operator+(const Node &o) const    {        return Node(            max(h, w + o.h),            max(max(j, o.j), m + o.h),            max(m + o.w, o.m),            w + o.w);    }}; Node solve1(int h, int m){    if (h > m)        return Node(-1, -1, -1, -1);    if (h == m)        return Node(max(a[h], 0), max(a[h], 0), max(a[h], 0), a[h]);    int j = (h + m) >> 1;    return solve1(h, j) + solve1(j + 1, m);} int solve2(int h, int m){    if (h > m)        return -1;    if (h == m)        return max(a[h], 0);    int j = (h + m) >> 1;    int wh = 0, wm = 0;    int wht = 0, wmt = 0;    for (int i = j; i >= h; i--) {        wht += a[i];        wh = max(wh, wht);    }    for (int i = j + 1; i <= m; i++) {        wmt += a[i];        wm = max(wm, wmt);    }    return max(max(solve2(h, j), solve2(j + 1, m)), wh + wm);} int main(){    cin >> n;    for (int i = 1; i <= n; i++) cin >> a[i];    cout << solve1(1, n).j << endl;    cout << solve2(1, n) << endl;    return 0;}

假设输入的所有数的绝对值都不超过 10001000 ,完成下面的判断题和单选题:

第26题单选题原卷 3 分

solve2(1, n) 的时间复杂度为( )。

填写答案